Using radioactive decay: A=A0(21)t/t1/2.
With 75% activity remaining: 0.75=(21)x/245.
Taking log base 10: log(0.75)=245xlog(0.5).
Calculate: log(0.75)=log3−log4=0.4771−2(0.3010)=−0.1249 and log(0.5)=−0.3010.
Thus −0.1249=245x×(−0.3010), giving x=0.30100.1249×245=101.66≈102 days (nearest integer).