The cell reaction is Zn(s)+2Ag+(aq)→Zn2+(aq)+2Ag(s)
The standard cell potential is given by:
Ecell∘=Ecathode∘−Eanode∘=0.80−(−0.76)=1.56 V
Using the Nernst equation:
Ecell=Ecell∘−n0.059log[Ag+]2[Zn2+]
Substituting the given values (n=2, [Zn2+]=1 M, Ecell=1.60 V):
1.60=1.56−20.059logx21
0.04=−20.059(−2logx)
0.04=0.059logx
logx=0.0590.04=5.94
Answer: 5.94