
pOH=pKb+log[BaseSalt]
5=5.699+log[BaseSalt]
y−xx=51
6x=y
7x=100
x=7100 ml
y=7600 ml
JEE Main 2026 — Chemistry Physical Chemistry
Consider a weak base ' B ' of pKb=5.699. ' x ' mL of 0.02 M HCl and ' y ' mL of 0.02 M weak base ' B ' are mixed to make 100 mL of a buffer of pH 9 at 25∘C. The values of ' x ' and ' y ' respectively are: [Given: log2=0.3010,log3=0.4771,log5=0.699]
Held on 28 Jan 2026 · Verified 6 Jul 2026.
x85.7y14.3
x14.3y85.7
x11.1y88.9
x42.7y57.3
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