MnO4−+I−→MnO2+I2
I2+S2O32−→S4O62−+I−
gram eq of KMnO4 = gram eq of Na2S2O3
0.2×1000500×3=0.1×V×1
V=3 L
500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2MKMnO4 solution in basic medium. The liberated iodine was titrated with standard 0.1MNa2 S2O3 solution in the presence of starch indicator till the blue color disappeared. The volume (in L) of Na2 S2O3 consumed is ____. (Nearest integer)
Held on 28 Jan 2026 · Verified 6 Jul 2026.
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