Reaction: A + 2B → AB₂.
Moles of A = 36.0/60 = 0.6 mol;
Moles of B = 56.0/80 = 0.7 mol.
A requires 1.2 mol of B but only 0.7 available, so B is limiting reagent.
So, (A) False - B is limiting.
(B) AB₂ formed = 0.7/2 = 0.35 mol;
Molar mass AB₂ = 60 + 2(80) = 220 g/mol;
Mass = 0.35 × 220 = 77 g True.
(C) False - Molar mass is 220 g/mol.
(D) A remaining = 0.6 - 0.35 = 0.25 mol = 15 g True.
Correct statements: B and D.
A+2 ~B longrightarrow AB_2 36.0 g of 'A' (Molar mass: 60 ~g ~mol^-1) and 56.0 g of ' B^prime (Molar mass: 80 ~g ~mol^-1) are allowed to react. Which…
JEE Main 2026 — Chemistry Physical Chemistry
A+2 B⟶AB2
36.0 g of 'A' (Molar mass: 60 g mol−1) and 56.0 g of ' B′ (Molar mass: 80 g mol−1) are allowed to react. Which of the following statements are correct ?
A. 'A' is the limiting reagent.
B. 77.0 g of AB2 is formed.
C. Molar mass of AB2 is 140 g mol−1.
D. 15.0 g of A is left unreacted after the completion of reaction.
Choose the correct answer from the options given below :
Held on 22 Jan 2026 · Verified 1 Jul 2026.
Options
- A
C and D Only
- B
A and B Only
- C
A and C Only
- D
B and D Only
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