Reaction: A + 2B → AB₂.
Moles of A = 36.0/60 = 0.6 mol;
Moles of B = 56.0/80 = 0.7 mol.
A requires 1.2 mol of B but only 0.7 available, so B is limiting reagent.
So, (A) False - B is limiting.
(B) AB₂ formed = 0.7/2 = 0.35 mol;
Molar mass AB₂ = 60 + 2(80) = 220 g/mol;
Mass = 0.35 × 220 = 77 g True.
(C) False - Molar mass is 220 g/mol.
(D) A remaining = 0.6 - 0.35 = 0.25 mol = 15 g True.
Correct statements: B and D.