4Al+3O2⟶2Al2O32781=3 mole 32128=4 mole Limiting reagent $\begin{aligned}
& \therefore \text { mole of } \mathrm{Al}_2 \mathrm{O}_3 \text { formed }=\frac{1}{2} \times 3 \text { mole } \
& \therefore \text { wt. of } \mathrm{Al}_2 \mathrm{O}_3 \text { formed }=\frac{3}{2} \times 102 \
& \quad=153 \mathrm{gm}
\end{aligned}$