Let moles of CO2=n moles of Ca(OH)2 total initially =2n excess Ca(OH)2=n gm equivalent of Ca(OH)2=gm equivalent of HCl $\begin{aligned}
& \mathrm{n} \times 2=0.1 \times \frac{40}{1000} \times 1 \
& \mathrm{n}=2 \times 10^{-3}
\end{aligned}Volumeof\mathrm{CO}_2=2 \times 10^{-3} \times 22400=44.8 \mathrm{~cm}^3$
Some CO_2 gas was kept in a sealed container at a pressure of 1 atm and at 273 K . This entire amount of CO_2 gas was later passed through an aqueous…
JEE Main 2025 — Chemistry Physical Chemistry
2025integerhard
Some CO2 gas was kept in a sealed container at a pressure of 1 atm and at 273 K . This entire amount of CO2 gas was later passed through an aqueous solution of Ca(OH)2. The excess unreacted Ca(OH)2 was later neutralized with 0.1 M of 40 mL HCl . If the volume of the sealed container of CO2 was x, then x is ________ cm3 (nearest integer). [Given : The entire amount of CO2( g) reacted with exactly half the initial amount of Ca(OH)2 present in the aqueous solution.]
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Held on 22 Jan 2025 · Verified 6 Jul 2026.
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