$\begin{aligned}
& \mathrm{W}_{1 \rightarrow 2}=0 \
& \mathrm{W}_{2 \rightarrow 3}=-\mathrm{P} \Delta \mathrm{V} \
& =-3[2-1] \
& =-3 \mathrm{~atm}-\ell
\end{aligned}$
W3→4=0
Total work done
$\begin{aligned}
& =-3 \mathrm{~atm}-\ell \
& =-3 \times 101.3 \text { Joule } \
& =-304 \text { Joule }
\end{aligned}$
