$\begin{aligned}
& \underset{-5^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{s})} \rightarrow \underset{0^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{s})} ; \Delta \mathrm{S}1=\int{268 \mathrm{K}}^{273 \mathrm{K}} \frac{\mathrm{C}_{\mathrm{p}}, \mathrm{m} \mathrm{dT}}{\mathrm{T}} \
& \underset{0^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{s})} \rightleftharpoons \underset{0^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{l})} ; \Delta \mathrm{S}2=\frac{\Delta \mathrm{H}{\mathrm{m}} \text {, fus }}{273} \
& \underset{0^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{I})} \rightarrow \underset{100^{\circ} \mathrm{C}}{\mathrm{H}2 \mathrm{O}(\mathrm{I})} ; \Delta \mathrm{S}3=\int{273}^{373} \frac{\mathrm{C}{\mathrm{p}}, \mathrm{m} \mathrm{dt}}{\mathrm{T}} \
& \underset{100^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{l})} \rightleftharpoons \underset{100^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{g})} ; \Delta \mathrm{S}4=\frac{\Delta \mathrm{H}{\mathrm{m}} \text {, vap }}{373} \
& \underset{100^{\circ} \mathrm{C}}{\mathrm{H}2 \mathrm{O}(\mathrm{g})} \rightarrow \underset{110^{\circ} \mathrm{C}}{\mathrm{H}_2 \mathrm{O}(\mathrm{g})} ; \Delta \mathrm{S}5=\int{373}^{383} \frac{\mathrm{C}_{\mathrm{p}, \mathrm{m}} \mathrm{dT}}{\mathrm{T}} \
& \Delta \mathrm{~S}{\text {total }}=\Delta \mathrm{S}_1+\Delta \mathrm{S}_2+\Delta \mathrm{S}_3+\Delta \mathrm{S}_4+\Delta \mathrm{S}_5
\end{aligned}$
JEE Main 2025 — Chemistry Physical Chemistry
2025mcqhard
Ice at −5∘C is heated to become vapor with temperature of 110∘C at atmospheric pressure. The entropy change associated with this process can be obtained from
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Held on 23 Jan 2025 · Verified 6 Jul 2026.
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