$\begin{aligned}
& \text { moles of } \mathrm{Fe}_3 \mathrm{O}_4=\frac{2.32 \times 10^3 \times 10^3}{232}=10000 \mathrm{mol} \
& \text { moles of } \mathrm{CO}=\frac{2.8 \times 10^2 \times 10^3}{28}=10000 \mathrm{mol} \
& \mathrm{Fe}_3^3 \mathrm{O}_4+4 \mathrm{CO} \longrightarrow 3 \mathrm{Fe}+4 \mathrm{CO}_2 \
& 10^4 \mathrm{mol} \quad 10^4 \mathrm{mol}
\end{aligned}COisL.R.moleof\mathrm{Fe}=\frac{3}{4} \times 10^4massof\mathrm{Fe}=\frac{3}{4} \times \frac{10^4 \times 56}{1000} \mathrm{kg}=420 \mathrm{kg}$