Volume of silver coating =0.05×0.05×10000=25cm3
Given, Density =7.9gcm−3
Density = Mass/ Volume
Mass of silver deposited =25×7.9g
Moles of silver atoms = mass / molar mass =10825×7.9
Number of silver atoms =10825×7.9×6.023×1023
=11.01×1023
Ans. 11
JEE Main 2024 — Chemistry Physical Chemistry
0.05cm thick coating of silver is deposited on a plate of 0.05m2 area. The number of silver atoms deposited on plate are _______×1023. (At mass Ag =108,d=7.9gcm−3) Round off to the nearest integer.
Held on 30 Jan 2024 · Verified 6 Jul 2026.
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