1000 ml solution contains 0.8mol of H2SO4
Mass of solution = 100cm3×1.06cm3g=1060g
Mass of solute (H2SO4) =0.8×98=78.4g
Mass of solvent = 1060−78.4=981.6g
Molality=massofsolvent(inkg)molesofH2SO4
=981.6×10−30.8=0.815m
= 815×10−3m
JEE Main 2024 — Chemistry Physical Chemistry
Molality of 0.8MH2SO4 solution (density 1.06gcm−3 ) is _______×10−3m.
Round off your answer to the nearest integer.
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