Ka of CH3COOH=1.8×10−5
Ka of NH4OH=1.8×10−5
We know that pH of solution of the salt made up of weak acid (CH3COOH) and weak base (NH4OH) can be found using formula
pH=7+21[pKa−pKb]
pKa=−log(Ka)
=−log(1.8×10−5)=−[log1.8+log10−5]=−[0.2553−5]=+4.7447pKb=−log(Kb)=−log(1.8×10−5)=4.7447pH=7+21[4.7447−4.7447]=7+0=7
If Ka=Kb, then pH of salt is always 7.
Therefore, the pH of given solution is 7.