2 A( g)+B(g)⟶C(g)
$\begin{array}{ll}
\mathrm{r}1 & 1.5 \mathrm{atm} \quad 0.7 \mathrm{atm} \
\mathrm{r}2 & 0.5 \mathrm{atm} \quad 0.2 \mathrm{atm} \quad 0.5 \mathrm{~atm} \
& \because \mathrm{r}=\mathrm{K}\left[\mathrm{P}{\mathrm{A}}\right]^2\left[\mathrm{P}{\mathrm{B}}\right] \
& \mathrm{r}_1=\mathrm{K}[1.5]^2[0.7] \
& \mathrm{r}_2=\mathrm{K}[0.5]^2[0.2] \
& \frac{\mathrm{r}_1}{\mathrm{r}_2}=9 \times \frac{7}{2}=31.5=315 \times 10^{-1}
\end{array}$ Ans. 315