JEE Main 2023 — Chemistry Physical Chemistry

2023integereasy

If $5$ moles of ${\mathrm{BaCl}}_{2}$ is mixed with $2$ moles of ${\mathrm{Na}}_{3}{\mathrm{PO}}_{4},$ the maximum number of moles of ${\mathrm{Ba}}_{3}{({\mathrm{PO}}_{4})}_{2}$ formed is $_________$ (Nearest integer)

Official previous-year question

Held on 6 Apr 2023 · Verified 6 Jul 2026.

Did you get this right?

Solution

The balanced chemical equation for the reaction between ${\mathrm{BaCl}}_{2}$ and ${\mathrm{Na}}_{3}{\mathrm{PO}}_{4}$ is:

$3{\mathrm{BaCl}}_{2}+2{\mathrm{Na}}_{3}{\mathrm{PO}}_{4}\rightarrow {\mathrm{Ba}}_{3}({\mathrm{PO}}_{4}{)}_{2}+6\mathrm{NaCl}$

$5$ moles of barium chloride will require $\frac{5\times 2}{3}=3.3$ moles of sodium phosphate.

Here, sodium phosphate is the limiting reagent.

$2$ moles of sodium phosphate produce $1$ mole of barium phosphate.

Thus, $2$ moles of sodium phosphate will produce $1$ mole of barium phosphate.

Hence, the maximum no. of moles of ${\mathrm{Ba}}_{3}({\mathrm{PO}}_{4}{)}_{2}$ that can be formed is one mole.

Your note

JEE Main Physical Chemistry in other years

Physical Chemistry 2026 Physical Chemistry 2025 Physical Chemistry 2024 Physical Chemistry 2022 Physical Chemistry 2021 Physical Chemistry 2020 Physical Chemistry 2019 Physical Chemistry 2018 Physical Chemistry 2017 Physical Chemistry 2016 Physical Chemistry 2015 Physical Chemistry 2014

Keep practicing Physical Chemistry

Work through every JEE Main Physical Chemistry PYQ, year by year.

Browse all Chemistry topics

JEE Main 2023 — Chemistry Physical Chemistry

2023integereasy

Official previous-year question

Held on 6 Apr 2023 · Verified 6 Jul 2026.

Did you get this right?

Solution

The balanced chemical equation for the reaction between ${\mathrm{BaCl}}_{2}$ and ${\mathrm{Na}}_{3}{\mathrm{PO}}_{4}$ is:

$3{\mathrm{BaCl}}_{2}+2{\mathrm{Na}}_{3}{\mathrm{PO}}_{4}\rightarrow {\mathrm{Ba}}_{3}({\mathrm{PO}}_{4}{)}_{2}+6\mathrm{NaCl}$

$5$ moles of barium chloride will require $\frac{5\times 2}{3}=3.3$ moles of sodium phosphate.

Here, sodium phosphate is the limiting reagent.

$2$ moles of sodium phosphate produce $1$ mole of barium phosphate.

Thus, $2$ moles of sodium phosphate will produce $1$ mole of barium phosphate.

Hence, the maximum no. of moles of ${\mathrm{Ba}}_{3}({\mathrm{PO}}_{4}{)}_{2}$ that can be formed is one mole.

JEE Main 2023 — Chemistry Physical Chemistry

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry

JEE Main 2023 — Chemistry Physical Chemistry

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry