(A) 2CO(g)+O2(g)→2CO2(g)ΔH1o=−xkJmol−1
(B) Cgraphite+O2(g)→CO2(g)ΔH2o=−ykJmol−1
If the equation is multiplied the value n, then the enthalpy change value also multiplied by factor n. If the enthalpy is positive in one direction, it is negative in other direction.
Multiply equation B by 2 and subtract equation (A) from it
2Cgraphite+O2(g)→2CO(g)ΔH∘=x−2y
Cgraphite+21O2→CO;ΔH∘=2x−2y