JEE Main 2022 — Chemistry Physical Chemistry

2022integerhard

For a cell, $\mathrm{Cu}(s){\mathrm{Cu}}^{2+}(0.001M)|{\mathrm{Ag}}^{+}(0.01M)|\mathrm{Ag}(s)$ the cell potential is found to be $0.43V$ at $298K$ . The magnitude of standard electrode potential for ${\mathrm{Cu}}^{2+}|\mathrm{Cu}$ is____ $\times {10}^{-2}V$

$[\mathrm{Given}:{E}_{{\mathrm{Ag}}^{+}/\mathrm{Ag}}^{\Theta }=0.80V\mathrm{and}\frac{2.303\mathrm{RT}}{F}=0.06V]$

Official previous-year question

Held on 29 Jul 2022 · Verified 6 Jul 2026.

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Solution

At anode $\mathrm{Cu}\rightarrow {\mathrm{Cu}}^{2+}+2{e}^{-}$

At cathode $2{\mathrm{Ag}}^{+}+2{e}^{-}\rightarrow 2\mathrm{Ag}$

Cell reaction $\rightarrow \mathrm{Cu}+2{\mathrm{Ag}}^{+}\rightarrow {\mathrm{Cu}}^{2+}+2\mathrm{Ag}$

${E}_{\mathrm{cell}}={E}_{\mathrm{cell}}^{0}-\frac{0.06}{2}\mathrm{log}\frac{[{\mathrm{Cu}}^{2+}]}{{[{\mathrm{Ag}}^{+}]}^{2}}$

$0.43={E}_{\mathrm{cell}}^{0}-\frac{0.06}{2}\mathrm{log}\frac{(0.001)}{{(0.01)}^{2}}$

${E}_{\mathrm{cell}}^{0}=0.46$

${E}_{\mathrm{cell}}^{0}={E}_{{\mathrm{Ag}}^{+}/\mathrm{Ag}}^{0}-{E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}$

$0.46=0.80-{E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}$

${E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}=0.34$ volt

${E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}=34\times {10}^{-2}$

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JEE Main 2022 — Chemistry Physical Chemistry

2022integerhard

$[\mathrm{Given}:{E}_{{\mathrm{Ag}}^{+}/\mathrm{Ag}}^{\Theta }=0.80V\mathrm{and}\frac{2.303\mathrm{RT}}{F}=0.06V]$

Official previous-year question

Held on 29 Jul 2022 · Verified 6 Jul 2026.

Did you get this right?

Solution

At anode $\mathrm{Cu}\rightarrow {\mathrm{Cu}}^{2+}+2{e}^{-}$

At cathode $2{\mathrm{Ag}}^{+}+2{e}^{-}\rightarrow 2\mathrm{Ag}$

Cell reaction $\rightarrow \mathrm{Cu}+2{\mathrm{Ag}}^{+}\rightarrow {\mathrm{Cu}}^{2+}+2\mathrm{Ag}$

${E}_{\mathrm{cell}}={E}_{\mathrm{cell}}^{0}-\frac{0.06}{2}\mathrm{log}\frac{[{\mathrm{Cu}}^{2+}]}{{[{\mathrm{Ag}}^{+}]}^{2}}$

$0.43={E}_{\mathrm{cell}}^{0}-\frac{0.06}{2}\mathrm{log}\frac{(0.001)}{{(0.01)}^{2}}$

${E}_{\mathrm{cell}}^{0}=0.46$

${E}_{\mathrm{cell}}^{0}={E}_{{\mathrm{Ag}}^{+}/\mathrm{Ag}}^{0}-{E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}$

$0.46=0.80-{E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}$

${E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}=0.34$ volt

${E}_{{\mathrm{Cu}}^{2+}/\mathrm{Cu}}^{0}=34\times {10}^{-2}$

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JEE Main Physical Chemistry in other years

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JEE Main 2022 — Chemistry Physical Chemistry

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JEE Main 2022 — Chemistry Physical Chemistry

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Solution

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JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

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