Milli equivalents of HCl(NaVa)=50×1=50
Milli equivalents of NaOH(NbVb)=30×1=30
Since NaVa>NbVb
[H+]=Va+VbNaVa−NbVb=8050−30=8020=0.25=2.5×10−1
pH=−log[H+]=−log(2.5×10−1)=1−0.3979=0.6021
pH×104=0.6021×104=6021
JEE Main 2021 — Chemistry Physical Chemistry
The pH of a solution obtained by mixing 50mL of 1MHCl and 30mL of 1MNaOH is x×10−4. The value of x is (Nearest integer)
[log2.5=0.3979]
Held on 31 Aug 2021 · Verified 6 Jul 2026.
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