ΔTb=i×kb×molality ; m=GMM1w1×w21000
For Acetone solution
0.17=1×1.7×GMM1.22×1001000
GMM of substance =122gm/mol
For Benzene solution
ΔTb=i×kb×m=21×2.6×1221.22×1001000=0.13=13×10−2
=13
JEE Main 2021 — Chemistry Physical Chemistry
1.22g of an organic acid is separately dissolved in 100g of benzene (Kb=2.6Kkgmol−1) and 100g of acetone (Kb=1.7Kkgmol−1). The acid is known to dimerize in benzene but remain as a monomer in acetone. The boiling point of the solution in acetone increases by 0.17∘C. The increase in boiling point of solution in benzene inC∘ is x×10−2. The value of x is (Nearest integer)
[Atomic mass : C=12.0,H=1.0,O=16.0]
Held on 31 Aug 2021 · Verified 6 Jul 2026.
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