For 1st order reaction,
K=t2.303⋅log[At][A0]=570sec2.303⋅log(32100)
=1.999×10−3sec−1≈2×10−3sec−1
JEE Main 2021 — Chemistry Physical Chemistry
For a certain first order reaction 32 of the reactant is left after 570s. The rate constant of this reaction is ×10−3s−1. (Round off to the Nearest Integer).
[Given: log102=0.301,ln10=2.303]
Held on 17 Mar 2021 · Verified 6 Jul 2026.
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