VNaOH=4.4ml
eq. of NaOH= eq. of H2C2O4
or, M×4.4×1=1.25×10×2
or, M=5.68M
∴ Nearest integer answer is 6.
JEE Main 2021 — Chemistry Physical Chemistry
Consider titration of NaOH solution versus 1.25M oxalic acid solution. At the end point following burette readings were obtained.
(i) 4.5mL
(ii) 4.5mL
(iii) 4.4mL
(iv) 4.4mL
(v) 4.4mL
If the volume of oxalic acid taken was 10.0mL then the molarity of the NaOH solution is ___M. (Rounded-off to the nearest integer)
Held on 25 Feb 2021 · Verified 6 Jul 2026.
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