T=298K,R=8.314molKJ
→ Chemical reaction is
50gFe+2HCl→P=1barFeCl2+H2(g)
=55.8550mol
→ Work done for 1mol gas
=−Pext×ΔV
=ΔngRT
=−1×8.314×298J
→ Work done for 55.8550 mol of gas
=−8.314×298×55.8550J
=−2218.059J
≃−2218J
JEE Main 2021 — Chemistry Physical Chemistry
At 25∘C,50g of iron reacts with HCl to form FeCl2. The evolved hydrogen gas expands against a constant pressure of 1bar. The work done by the gas during this expansion is -_______ J.
(Round off to the Nearest Integer)
[Given : R=8.314Jmol−1K−1. Assume, hydrogen is an ideal gas]
[Atomic mass off Fe is 55.85u]
Held on 16 Mar 2021 · Verified 6 Jul 2026.
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