MH2SO4⇒98×1009.8=10−3
MNaOH⇒40×1004=10−3
=5040×10−3−10×10−3×2=5020×10−3
[OH−]=52×10−3=4×10−4
pOH=4−log4=3.4pH=14−3.4=10.6
Two solutions, A and B, each of 100L was made by dissolving 4g of NaOH and 9.8g of H2SO4 in water, respectively. The pH of the resultant solution obtained from mixing 40L of solution A and 10L of solution B is ____________. (log2=0.3)
Held on 7 Jan 2020 · Verified 6 Jul 2026.
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