For n=5 5s,5p,5d,5f and 5g and subshell is available
In 5s→1orbital
5p→3orbital
5d→5 orbital
5f→7orbital
5g→9orbital
In each subshell 1 electron of every orbital will belong to m5=+21 So, Total number of orbitals that will be associate with m5=+21 will be 1+3+5+7+9=25