Let mass of pure H2O2 is x gram
+7MnO4−+−1H2O2vf=2→+2Mn2++0O2
Eq. of H2O2=Eq. of MnO4−
[34x]2=[1580.316]5
x=0.17
So, purity of H2O2 solution =0.20.17×100=85
A 20.0mL solution containing 0.2g impure H2O2 reacts completely with 0.316g of KMnO4 in acid solution. The purity of H2O2 (in ) is______ (mol. wt. of H2O2=34; mol. wt. of KMnO4=158)
Held on 4 Sept 2020 · Verified 6 Jul 2026.
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