Final temperature =2T1+T2, let T2>T ∴dS=Tdq=TCpdT ∴ΔS=Cpln(TiTf) ∴ΔSTotal =Cpln(2 T1T1+T2)+Cpln(2 T2T1+T2) =Cpln[4 T1 T2(T1+T2)2]
Two blocks of the same metal having same mass and at temperature T1, and T2, respectively, are brought in contact with each other and allowed to attain thermal equilibrium at constant pressure. The change in entropy, ΔS, for this process is :
Held on 11 Jan 2019 · Verified 6 Jul 2026.
CPln[4 T1 T2(T1+T2)2]
2Cpln[T1T2(T1+T2)21]
2CPln(4 T1 T2T1+T2)
2CPln[2 T1 T2T1+T2]
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