Freezing point of diluted milk =−0.2∘C ΔTf∗=0.2∘C Free ring point ol pure milk =−0.5∘C ΔTf=0.5∘C ΔTf′ΔTf= Kf×m′Kf×m;m= mass of solvent (kg) mole of solute Moles of solute are same in both samples. ∴0.20.5= WWn WW′=25;W′=25 W 2 cups of pure milk is mixed with 3 cups of water to make 5 cups of diluted milk.
The freezing point of a diluted milk sample is found to be -0.2° C, while it should have been -0.5° C for pure milk. How much water has been added to…
JEE Main 2019 — Chemistry Physical Chemistry
2019mcqhard
The freezing point of a diluted milk sample is found to be −0.2∘C, while it should have been −0.5∘C for pure milk. How much water has been added to pure milk to make the diluted sample?
Official previous-year question
Held on 11 Jan 2019 · Verified 6 Jul 2026.
Options
- A
1 cup of water to 2 cups of pure milk
- B
3 cups of water to 2 cups of pure milk
- C
1 cup of water to 3 cups of pure milk
- D
2 cups of water to 3 cups of pure milk
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Physical Chemistry in other years
More JEE Main Physical Chemistry questions
What is the ratio of wave number of first line (lowest energy line) of Balmer series of H atomic spectrum to first line of its Brackett series?
2026medium
  Which of the following point in Figure 2 most accurately represents the nodal surface as shown in Figure 1?
2026medium
At 298 K, the mole percentage of $\mathrm{N}_{2}(\mathrm{~g})$ in air is $80 \%$. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of $\mathrm{N}_{2}(\mathrm{~g})$ in water at 298 K ? ($\mathrm{K}_{\mathrm{H}}$ for $\mathrm{N}_{2}$ is $6.5 \times 10^{7} \mathrm{~mm} \mathrm{Hg}$)
2026medium
Electricity is passed through an acidic solution of $\mathrm{Cu}^{2+}$ till all the $\mathrm{Cu}^{2+}$ was exhausted, leading to the deposition of 300 mg of Cu metal. However, a current of 600 mA was continued to pass through the same solution for another 28 minutes by keeping the total volume of the solution fixed at 200 mL. The total volume of oxygen evolved at STP during the entire process is $\_\_\_\_$ mL. (Nearest integer) [Given: $\mathrm{Cu}^{2+}(\mathrm{aq})+2 \mathrm{e}^{-} \rightarrow \mathrm{Cu}(\mathrm{s}) \mathrm{E}_{\text {red }}^{\mathrm{o}}=+0.34 \mathrm{~V}$ $\mathrm{O}_{2}(\mathrm{~g})+4 \mathrm{H}^{+}+4 \mathrm{e}^{-} \rightarrow 2 \mathrm{H}_{2} \mathrm{O} \mathrm{E}_{\text {red }}^{\mathrm{o}}=+1.23 \mathrm{~V}$ Molar mass of $\mathrm{Cu}=63.54 \mathrm{~g} \mathrm{~mol}^{-1}$ Molar mass of $\mathrm{O}_{2}=32 \mathrm{~g} \mathrm{~mol}^{-1}$ Faraday Constant $=96500 \mathrm{C} \mathrm{mol}^{-1}$ Molar volume at $\mathrm{STP}=22.4 \mathrm{~L}$]
2026hard
Arrange the following resultant mixtures in increasing order of their pH values A. $10$ mL $0.2$ M Ca(OH)$_2$ + $25$ mL $0.1$ M HCl B. $10$ mL $0.01$ M H$_2$SO$_4$ + $10$ mL $0.01$ M Ca(OH)$_2$ C. $10$ mL $0.1$ M H$_2$SO$_4$ + $10$ mL $0.1$ M KOH Choose the correct answer from the options given below:
2026medium
Other Chemistry topics for JEE Main
Keep practicing Physical Chemistry
Work through every JEE Main Physical Chemistry PYQ, year by year.