millimoles of oxalic acid =50×0.5
milli equivalent of oxalic acid =50×0.5×2
millimoles of NaOH=25×M= milli equivalent of NaOH
∴50×0.5×2=25×M
⇒M=2
M=2 so, 1000ml NaOH solution contains
=2 mol of NaOH
=2×40=80g NaOH
∴50ml NaOH solution contains =100080×50=4g