No. of moles of oxygen in 0.16 g of oxygen molecule =32 g/mol0.16 g=0.005 mole 2NaClO3⟶Δ2NaCl+3O2 According to the reaction, 3 moles of O2=2 moles of NaCl =2 moles of AgCl Molar mass of AgCl=143.5 g/mol 0.005 moles of O2 will ppt. =0.005×32 moles AgCl =0.0033 moles of AgCl ∴ Mass of AgCl (in g) obtained will be =143.5 g/mol×0.0033 moles =0.48 g.
A sample of NaClO_3 is converted by heat to NaCl with a loss of 0.16 ~g of oxygen. The residue is dissolved in water and precipitated as AgCl. The…
JEE Main 2018 — Chemistry Physical Chemistry
A sample of NaClO3 is converted by heat to NaCl with a loss of 0.16 g of oxygen. The residue is dissolved in water and precipitated as AgCl. The mass of AgCl (in g) obtained will be: (Given: Molar mass of AgCl=143.5 g mol−1 )
Held on 15 Apr 2018 · Verified 6 Jul 2026.
Options
- A
0.35
- B
0.54
- C
0.41
- D
0.48
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