JEE Main 2017 — Chemistry Physical Chemistry

2017mcqmedium

Consider the following standard electrode potentials ( ${\text{E}}^{\text{o}}$ in volts) in aqueous solution:

$\begin{matrix}\underset{}{\text{E}\text{l}\text{e}\text{m}\text{e}\text{n}\text{t}} & \underset{}{{\text{M}}^{3+}/\text{M}} & \underset{}{{\text{M}}^{+}/\text{M}} \\ \text{A}\text{l} & -1.66 & +0.55 \\ \text{T}\text{l} & +1.26 & -0.34\end{matrix}$

Based on these data, which of the following statements is correct?

Official previous-year question

Held on 8 Apr 2017 · Verified 6 Jul 2026.

Options

A
$\text{T}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{3+}$
B
$\text{A}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{3+}$
C
$\text{T}{\text{l}}^{3+}$ is more stable than $\text{A}{\text{l}}^{3+}$
D
$\text{T}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{+}$

Did you get this right?

Solution

$\Delta {\text{G}}^{\text{o}}=-\text{n}\text{F}{\text{E}}^{\text{o}}$

if ${\text{E}}^{\text{o}}= \text{p}\text{o}\text{s}\text{i}\text{t}\text{i}\text{v}\text{e};$ then $\Delta {\text{G}}^{\text{o}}=\text{n}\text{e}\text{g}\text{a}\text{t}\text{i}\text{v}\text{e}$ ,

For those, conversions whose ${\text{E}}^{\text{o}}$ values are more positive are more favourable.

As we can see from then electrode potential data, that reduction of ${\mathrm{Al}}^{+}$ is spontaneous, but reduction of ${\mathrm{Tl}}^{+}$ is not. So, we can conclude from this that $\text{T}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{+}$

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Options

$\text{T}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{3+}$

$\text{A}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{3+}$

$\text{T}{\text{l}}^{3+}$ is more stable than $\text{A}{\text{l}}^{3+}$

$\text{T}{\text{l}}^{+}$ is more stable than $\text{A}{\text{l}}^{+}$

Solution

$\Delta {\text{G}}^{\text{o}}=-\text{n}\text{F}{\text{E}}^{\text{o}}$

if ${\text{E}}^{\text{o}}= \text{p}\text{o}\text{s}\text{i}\text{t}\text{i}\text{v}\text{e};$ then $\Delta {\text{G}}^{\text{o}}=\text{n}\text{e}\text{g}\text{a}\text{t}\text{i}\text{v}\text{e}$ ,

For those, conversions whose ${\text{E}}^{\text{o}}$ values are more positive are more favourable.

JEE Main 2017 — Chemistry Physical Chemistry

Options

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Solution

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JEE Main 2017 — Chemistry Physical Chemistry

Options

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry