ΔP=185−183=2 torr
MCH3−O∣∣C−CH3=15×2+16+12=58 g/mol
P0ΔP=185185−183=1852=XB=(M1.2)+58100M1.2
M1.2<<58100
⇒1852=M1.2×10058
M=10058×1.2×2185
=64.38≈64 g/mol
The vapour pressure of acetone at 20oC is 185torr. When 1.2g of a non-volatile substance was dissolved in 100g of acetone at 20oC , its vapour pressure was 183torr. The molar mass (gmol−1) of the substance is:
Held on 4 Apr 2015 · Verified 6 Jul 2026.
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