For the equilibrium, A(g)⇌B(g),ΔHis−40kJ/mol . If the ratio of the activation energies of the forward (Ef) and reverse (Eb) reactions is 32 then:
Held on 11 Apr 2015 · Verified 6 Jul 2026.
Ef=30kJ/mol, Eb=70kJ/mol
Ef=70kJ/mol, Eb=30kJ/mol
Ef=80kJ/mol, Eb=120kJ/mol
Ef=60kJ/mol,Eb=100kJ/mol
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The ratio of mass percentage (w/w) of C : H in a hydrocarbon is $12 : 1$. It has two carbon atoms. The weight (in g) of $CO_2(g)$ formed when $3.38$ g of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in g mol$^{-1}$ C : 12, H : 1, O : 16)
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