In an unknown compounds containing N and H given % of H=12.5% ∴% of N=100−12.5=87.5% Element HN Percentage 12.5%87.5 Atomic ratio 112.5=12.51487.5=6.25 Simple ratio 6.2512.5=26.256.25=1 2× vapour density = Mol. wt =16×2=32. Molecular formula =n× empirical formula mass n=1632=2 ∴ Molecular formula of the compound will be =(NH2)2 =N2H4