Quantity of Electricity =9650010×3600×2
=0.746≈0.75F.
If oxidation state is n+ for 1mol deposition of a metal:
Electricity=nF (Faradays)
For 0.250mol=0.250nF
∴0.250nF=0.75F
n=3
JEE Main 2014 — Chemistry Physical Chemistry
A current of 10.0A flows for 2.00h through an electrolytic cell containing a molten salt of metal X. This results in the decomposition of 0.250mol of metal X at the cathode. The oxidation state of X in the molten salt is:
(F=96,500C)
Held on 9 Apr 2014 · Verified 6 Jul 2026.
1+
4+
3+
2+
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