Consider the following… - JEE Main 2013 Chemistry PYQ

JEE Main 2013 — Chemistry Physical Chemistry

2013mcqmedium

Consider the following reaction:

$x {\mathrm{MnO}}_{4}^{-}+y {C}_{2}{O}_{4}^{2-}+{\mathrm{zH}}^{+}\longrightarrow x {\mathrm{Mn}}^{2+}+2y {\mathrm{CO}}_{2}+\frac{z}{2}{H}_{2}O$

The values of x, y and z in the reaction are, respectively:

Official previous-year question

Held on 7 Apr 2013 · Verified 6 Jul 2026.

Options

A
$2,5\mathrm{and}16$
B
$5,2\mathrm{and}8$
C
$5,2\mathrm{and}16$
D
$2,5\mathrm{and}8$

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Solution

$\begin{matrix} {\text{C}}_{2} {\text{O}}_{4}^{ 2 - } & \longrightarrow & 2 {\text{CO}}_{2} + 2 {\text{e}}^{-} ] \times 5 \\ {\text{MnO}}_{4}^{-} + 8 {\text{H}}^{+} + 5 {\text{e}}^{-} & \longrightarrow & {\text{Mn}}^{ 2 + } + 4 {\text{H}}_{2} \text{O} ] \times 2 \end{matrix}$

$\begin{matrix} 2 {\text{MnO}}_{4}^{-} + 1 6 {\text{H}}^{+} + 5 {\text{C}}_{2} {\text{O}}_{4}^{ 2 - } & \longrightarrow \end{matrix} 1 0 {\text{CO}}_{2} + 2 {\text{Mn}}^{ 2 + } + 8 {\text{H}}_{2} \text{O}$

${\text{MnO}}_{4}^{-} \Rightarrow \text{x} = 2$

${\text{C}}_{2} {\text{O}}_{4}^{ 2 - } \Rightarrow \text{y} = 5$

${\text{H}}^{+} \Rightarrow \text{z} = 1 6$

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Solution

${\text{MnO}}_{4}^{-} \Rightarrow \text{x} = 2$

${\text{C}}_{2} {\text{O}}_{4}^{ 2 - } \Rightarrow \text{y} = 5$

${\text{H}}^{+} \Rightarrow \text{z} = 1 6$

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Options

Did you get this right?

Solution

Your note

JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry