Rate 1=k[A]n[B]m; Rate 2=k[2 A]n[1/2 B]m ∴ Rate 1 Rate 2=k[A]n[ B]mk[2 A]n[1/2 B]m=[2]n[1/2]m=2n⋅2−m=2n−m
The rate law for a reaction between the substances A and B is given by Rate =k[A]n[B]m On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as
Held on 30 Apr 2003 · Verified 6 Jul 2026.
(m+n)
(n−m)
2(n−m)
2(m+n)1
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