In the haloform reaction:
(A) Sodium hypochlorite reacts with KI in acidic medium to generate the active halogenating species, forming KOI (potassium iodite/hypoidite). TRUE.
(B) KOI serves as an oxidizing agent (not reducing) in the reaction, converting methyl ketones to carboxylic acids. FALSE.
(C) α,β-unsaturated methylketones possess the essential methyl ketone group (CH3CO−) required for haloform reaction, allowing iodination and subsequent cleavage. TRUE.
(D) Isopropyl alcohol (CH3)2CHOH lacks a methyl ketone group, so it cannot undergo the haloform reaction. TRUE.
(E) Formic acid has no methyl ketone functionality, preventing haloform test. FALSE.
Therefore, statements A and C are true.