The given structures have a central carbon atom bonded to four groups: −Br, −Cl, −CH3, and −Me.
Since −CH3 and −Me both represent the same alkyl group (methyl), the central carbon atom is bonded to two identical groups.
For a carbon atom to be a chiral center, it must be bonded to four different groups. Because this condition is not met, the central carbon is not a stereocenter and the molecule is achiral.
Both structures represent the same achiral compound (2-bromo-2-chloropropane) drawn in slightly different orientations. Therefore, they are identical molecules.
Answer: identical molecules.
