JEE Main 2026 — Chemistry Organic Chemistry

2026integermedium

' $x$ ' is the product which is obtained from benzene by reacting it with carbon monoxide and hydrogen chloride in the presence of cuprous chloride. ' $y$ ' is the major product obtained from the benzene by reacting it with ethanoyl chloride in the presence of anhydrous AlCl $_3$ . Product (major) obtained by heating $x$ and $y$ in the presence of alkali is $z$ . Total number of $\pi$ (pi) electrons in $z$ is ________.

Official previous-year question

Held on 8 Apr 2026 · Verified 6 Jul 2026.

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Solution

Benzene reacts with $CO$ and $HCl$ in the presence of $CuCl$ to give benzaldehyde ( $x$ ) via the Gattermann-Koch reaction.

Benzene reacts with ethanoyl chloride ( $CH_3COCl$ ) in the presence of anhydrous $AlCl_3$ to give acetophenone ( $y$ ) via Friedel-Crafts acylation.

Heating benzaldehyde ( $x$ ) and acetophenone ( $y$ ) in the presence of alkali results in a crossed aldol condensation to form benzalacetophenone ( $z$ ).

$C_6H_5CHO + CH_3COC_6H_5 \xrightarrow{OH^-, \Delta} C_6H_5-CH=CH-CO-C_6H_5 + H_2O$

The structure of $z$ ( $C_6H_5-CH=CH-CO-C_6H_5$ ) contains two phenyl rings ( $6$ $\pi$ bonds), one $C=C$ double bond ( $1$ $\pi$ bond), and one $C=O$ double bond ( $1$ $\pi$ bond).

Total number of $\pi$ bonds = $6 + 1 + 1 = 8$

Total number of $\pi$ electrons = $8 \times 2 = 16$

Answer: $16$

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Solution

Benzene reacts with $CO$ and $HCl$ in the presence of $CuCl$ to give benzaldehyde ( $x$ ) via the Gattermann-Koch reaction.

Benzene reacts with ethanoyl chloride ( $CH_3COCl$ ) in the presence of anhydrous $AlCl_3$ to give acetophenone ( $y$ ) via Friedel-Crafts acylation.

Heating benzaldehyde ( $x$ ) and acetophenone ( $y$ ) in the presence of alkali results in a crossed aldol condensation to form benzalacetophenone ( $z$ ).

$C_6H_5CHO + CH_3COC_6H_5 \xrightarrow{OH^-, \Delta} C_6H_5-CH=CH-CO-C_6H_5 + H_2O$

The structure of $z$ ( $C_6H_5-CH=CH-CO-C_6H_5$ ) contains two phenyl rings ( $6$ $\pi$ bonds), one $C=C$ double bond ( $1$ $\pi$ bond), and one $C=O$ double bond ( $1$ $\pi$ bond).

Total number of $\pi$ bonds = $6 + 1 + 1 = 8$

Total number of $\pi$ electrons = $8 \times 2 = 16$

Answer: $16$

JEE Main 2026 — Chemistry Organic Chemistry

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JEE Main 2026 — Chemistry Organic Chemistry

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Solution

Your note

JEE Main Organic Chemistry in other years

More JEE Main Organic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Inorganic Chemistry

Keep practicing Organic Chemistry