In Carius method, sulfur is converted to BaSO4. Each mole of BaSO4 contains 1 mole of S.
Mass of S = 23332×1.2=0.1648 g
Percentage of S = 0.750.1648×100=21.97%
JEE Main 2026 — Chemistry Organic Chemistry
In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass 32 g mol−1). Molar mass of barium sulphate is 233 g mol−1.
Held on 21 Jan 2026 · Verified 6 Jul 2026.
10.30%
16.48%
21.97%
4.55%
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