When haloalkane or alkyl halide with a β hydrogen is heated with alcoholic solution of KOH, elimination of a hydrogen atom from β carbon and halogen atom from α−carbon occurs as a result, alkene is formed as product. Since β hydrogen atom is involved in the elimination reaction, it is often called β elimination. An alkene is formed. This alkene then on reaction with HBr undergoes addition reaction to give bromopropane, which on reaction with aqueous KOH gives alcohol, propan−2−ol.
