nCl in compound =nAgCl=(107.87+35.5)0.3849gg/mol
⇒ mass of chlorine =nCl×35.5=0.0953gm
⇒ wt. of chlorine =0.50.0953×100
=19.06
JEE Main 2021 — Chemistry Organic Chemistry
An organic compound is subjected to chlorination to get compound A using 5.0g of chlorine. When 0.5g of compound A is reacted with AgNO3 [Carius Method], the percentage of chlorine in compound A is when it forms 0.3849g of AgCl. (Round off to the Nearest Integer)
(Atomic masses of Ag and Cl are 107.87 and 35.5 respectively)
Held on 27 Jul 2021 · Verified 6 Jul 2026.
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