In XeO2F2: Xe has 8 valence electrons forming 4 bonding pairs (2 with O, 2 with F) and 2 lone pairs, giving a trigonal bipyramidal electron geometry with a see-saw molecular shape, making statement A TRUE.
Statement B is NOT TRUE because the total electron pairs around Xe is 6 (4 bonding + 2 lone), not 5.
For statement C, the O-Xe-O angle in a see-saw geometry is approximately 120°, not close to 180°, making it NOT TRUE.
Statement D is TRUE as the F-Xe-F angle is approximately 180° when F atoms occupy axial positions.
Statement E is NOT TRUE since Xe has only 8 valence electrons, not 16.
The incorrect statements are B, C, and E.