JEE Main 2026 — Chemistry Inorganic Chemistry

2026mcqhard

Identify the CORRECT set of details from the following:

A. $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ : Inner orbital complex; $\mathrm{d}^{2} \mathrm{sp}^{3}$ hybridized

B. $\left[\mathrm{MnCl}_{6}\right]^{3-}$ : Outer orbital complex; $\mathrm{sp}^{3} \mathrm{~d}^{2}$ hybridized

C. $\left[\mathrm{CoF}_{6}\right]^{3-}$ : Outer orbital complex; $\mathrm{d}^{2} \mathrm{sp}^{3}$ hybridized

D. $\left[\mathrm{FeF}_{6}\right]^{3-}$ : Outer orbital complex; $\mathrm{sp}^{3} \mathrm{~d}^{2}$ hybridized

E. $\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}$ : Inner orbital complex; $\mathrm{sp}^{3}$ hybridized

Choose the correct answer from the options given below:

Official previous-year question

Held on 23 Jan 2026 · Verified 6 Jul 2026.

Options

A
A, C & E Only
B
A, B & D Only
C
C & D Only
D
A, B, C, D & E

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Solution

Analyzing each complex based on Valence Bond Theory (VBT):

A. $[Co(NH_3)_6]^{3+}$ :

$Co^{3+}$ is $3d^6$ . $NH_3$ is a strong field ligand (SFL) for $Co^{3+}$ , causing pairing. This leaves two $3d$ orbitals vacant. Hybridization is $d^2sp^3$ (Inner orbital complex). Statement A is correct.

B. $[MnCl_6]^{3-}$ :

$Mn^{3+}$ is $3d^4$ . $Cl^-$ is a weak field ligand (WFL). No pairing occurs. To accommodate 6 ligands, it uses $4s$ , $4p$ , and $4d$ orbitals. Hybridization is $sp^3d^2$ (Outer orbital complex). Statement B is correct.

C. $[CoF_6]^{3-}$ :

$Co^{3+}$ is $3d^6$ . $F^-$ is a WFL. No pairing occurs. Hybridization is $sp^3d^2$ (Outer orbital complex). Statement C is incorrect because it mentions $d^2sp^3$ .

D. $[FeF_6]^{3-}$ :

$Fe^{3+}$ is $3d^5$ . $F^-$ is a WFL. No pairing occurs. Hybridization is $sp^3d^2$ (Outer orbital complex). Statement D is correct.

E. $[Ni(CN)_4]^{2-}$ :

$Ni^{2+}$ is $3d^8$ . $CN^-$ is a SFL, causing pairing of the two unpaired electrons in $3d$ . This leaves one $3d$ orbital vacant. Hybridization is $dsp^2$ (Square planar, Inner orbital complex). Statement E is incorrect because it mentions $sp^3$ .

Correct statements are A, B, and D.

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Solution

Analyzing each complex based on Valence Bond Theory (VBT):

A. $[Co(NH_3)_6]^{3+}$ :

B. $[MnCl_6]^{3-}$ :

C. $[CoF_6]^{3-}$ :

$Co^{3+}$ is $3d^6$ . $F^-$ is a WFL. No pairing occurs. Hybridization is $sp^3d^2$ (Outer orbital complex). Statement C is incorrect because it mentions $d^2sp^3$ .

D. $[FeF_6]^{3-}$ :

$Fe^{3+}$ is $3d^5$ . $F^-$ is a WFL. No pairing occurs. Hybridization is $sp^3d^2$ (Outer orbital complex). Statement D is correct.

E. $[Ni(CN)_4]^{2-}$ :

Correct statements are A, B, and D.

JEE Main 2026 — Chemistry Inorganic Chemistry

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JEE Main 2026 — Chemistry Inorganic Chemistry

Options

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Solution

Your note

JEE Main Inorganic Chemistry in other years

More JEE Main Inorganic Chemistry questions

Other Chemistry topics for JEE Main

Physical Chemistry

Organic Chemistry

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