Statement I: Let's analyze the geometry of the given species.
BF4−: sp3 hybridization, tetrahedral geometry. All B-F bond lengths are equal.
SiF4: sp3 hybridization, tetrahedral geometry. All Si-F bond lengths are equal.
XeF4: sp3d2 hybridization, square planar geometry. All Xe-F bond lengths are equal.
SF4: sp3d hybridization, see-saw geometry. It has axial and equatorial bonds. Axial bonds are longer than equatorial bonds due to greater repulsion. Thus, only SF4 has unequal bond lengths. The number of species is one, not two. Statement I is false.
Statement II: Bond order calculation using Molecular Orbital Theory:
Total electrons in O2− = 17, Bond Order = 1.5
Total electrons in O22− = 18, Bond Order = 1.0
Total electrons in F2 = 18, Bond Order = 1.0
Total electrons in O2+ = 15, Bond Order = 2.5
Among these, O2+ has the highest bond order (2.5), not O2−. Statement II is false.
Both Statement I and Statement II are false.