Electronegativity increases across a period from left to right. Nitrogen, oxygen, and fluorine belong to group 15, 16, and 17 respectively in the second period. Thus, the correct order of electronegativity is F>O>N. Statement I is true.
In OF2, fluorine is more electronegative than oxygen and always exhibits an oxidation state of −1. Let the oxidation state of oxygen be x. Then x+2(−1)=0⇒x=+2.
In Na2O, sodium is an alkali metal and exhibits an oxidation state of +1. Let the oxidation state of oxygen be y. Then 2(+1)+y=0⇒y=−2.
Statement II is also true.
Both Statement I and Statement II are true.
Answer: Both Statement I and Statement II are true