For Statement I:
Among N, As, Sb, P, the electronegativity order is N > P > As > Sb. Thus X = N (most electronegative) and Y = Sb (least electronegative). N2O3 is acidic (forms HNO₂ with water) and Sb2O3 is amphoteric (reacts with both acids and bases).
Statement I is true.
For Statement II:
While BCl3 is covalent and hydrolyzes in water to form B(OH)3, the hydrolysis products are incorrect. In neutral aqueous medium, B(OH)3 is formed. The tetrahedral [B(OH)4]− forms only in basic conditions, and boron does not form [B(H2O)6]3+ (boron is not a typical transition metal).
Statement II is false.