JEE Main 2026 — Chemistry Inorganic Chemistry

Statement I:

Aluminium reacts with aqueous sodium hydroxide to form sodium tetrahydroxoaluminate(III) and liberates hydrogen gas. The reaction is given by:

$$2Al + 2NaOH + 6H_2O \rightarrow 2Na^+[Al(OH)_4]^- + 3H_2$$2Al+2NaOH+6H2​O→2Na+[Al(OH)4​]−+3H2​

The complex ion formed is $[Al(OH)_4]^-$[Al(OH)4​]−, not $[Al(OH)_6]^{3-}$[Al(OH)6​]3−. Thus, Statement I is false.

Statement II:

For $ICl_4^-$ICl4−​, the central iodine atom has $7$7 valence electrons $+ 1$+1 (from negative charge) $= 8$=8 electrons. It forms $4$4 sigma bonds with Cl atoms and has $2$2 lone pairs. The hybridization is $sp^3d^2$sp3d2 and the shape is square planar.

For $ClO_3^-$ClO3−​, the central chlorine atom has $7$7 valence electrons $+ 1 = 8$+1=8 electrons. It forms $3$3 sigma bonds with O atoms and has $1$1 lone pair. The hybridization is $sp^3$sp3 and the shape is trigonal pyramidal.

For $IBr_2^-$IBr2−​, the central iodine atom has $7$7 valence electrons $+ 1 = 8$+1=8 electrons. It forms $2$2 sigma bonds with Br atoms and has $3$3 lone pairs. The hybridization is $sp^3d$sp3d and the shape is linear.

Thus, Statement II is true.

Therefore, Statement I is false but Statement II is true.

Answer: Statement I is false but Statement II is true