Analyzing geometry and hybridization:
A. IF₃: Iodine has 7 valence electrons, forms 3 bonds with F, leaving 2 lone pairs. Total electron pairs = 5 (trigonal bipyramidal geometry). Molecular shape is T-shaped. Hybridization = sp³d. CORRECT.
B. IF₅: Iodine forms 5 bonds with F and has 1 lone pair. Total electron pairs = 6 (octahedral geometry). Molecular shape is square pyramidal with 1 lone pair in axial position. Hybridization = sp³d². CORRECT.
C. IF₇: Iodine forms 7 bonds with F and has 0 lone pairs. Total electron pairs = 7. Molecular shape is pentagonal bipyramidal. Hybridization = sp³d³. CORRECT.
D. ClO₄⁻: Chlorine has 7 valence electrons + 1 from charge = 8. Bonded to 4 O atoms with 0 lone pairs. Total electron pairs = 4 (tetrahedral geometry). Molecular shape is tetrahedral, NOT square planar. Hybridization = sp³, NOT sp²d. INCORRECT.
Correct combinations: A, B, and C.