NH4++NaOH⟶H2O+NH3↑

NH3 is identify by K2[HgI4]+KOH
When a salt is treated with sodium hydroxide solution it gives gas X. On passing gas X through reagent Y a brown coloured precipitate is formed. X and Y respectively, are
Held on 7 Apr 2025 · Verified 6 Jul 2026.
X=NH3 and Y=HgO
X=NH3 and Y=K2HgI4+KOH
X=NH4Cl and Y=KOH
X=HCl and Y=NH4Cl
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